How to make Promise without returned value? about promises HOT 4 CLOSED

Hi @alexanderkhitev,

I've updated the answer above. Since 1.1.0 you can pass an arbitrary dispatch queue to the wrap operator (former resolve) to achieve the behavior you wanted. Let us know if still have any issues, we're happy to help.

Thanks.

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Hi Alex,

I imagine wrap could work for you?

private func updateName(_ name: String) -> Promise<Type> {
  return wrap(on: .global(qos: .default)) { handler in
    guard let userID = UserRealmManager().getUser()?.id else { throw CustomError }
    let ref = Database.database().reference().child(UsersPaths.Main.users.rawValue).child(userID)
    ref.updateChildValues([UsersPaths.UserProperties.displayName.rawValue : userID], handler)
  }
}

Where the Type of the promise would be the same as whatever the type of updateChildValues completion handler is. You may also need to specify the type of handler for wrap operator explicitly as (handler: @escaping (Type?, Error?) -> Void) to disambiguate between other wrap overloads.

If you'd like to use Void instead of that Type, you can chain another then at the end, like so:

return wrap { handler in
  //...
}.then { _ in () }

Where () constructs and returns an empty tuple, i.e. the value of type Void.

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Hi @shoumikhin

Thank you very much for your detailed answer.

I make all network logic in the background thread.

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Hi @alexanderkhitev and @shoumikhin, I use Void type for such cases:

Promise<Void> - it works great for cases, when you only need to check for the result:

  @discardableResult func logOut() -> Promise<Void> {
// Clear local storage
    return client.request(EXPIRE_TOKEN_API_ENDPOINT)
  }


// Somewhere in code

loginService.logOut()

or:
loginService.logOut().then .....

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