checking lat/lon in module netcdf_to_ee converter about geemap HOT 3 CLOSED

Please provide a complete script that can reproduce the issue.

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Having a netcdf file like in attachement (test_wu.nc):

nc_file = '.../test_wu.nc' #reading my nc file
ds = xr.open_dataset(nc_file) #opening using xarray
img=geemap.netcdf_to_ee(nc_file=nc_file, var_names='temperature', lon='lon', lat='lat') #conerting netcdf to ee

Error: The netCDF file is not a regular longitude/latitude grid

This error appear due to the geemap/geemap/common.py [line: 3262-3267]:
dim_lon = np.unique(np.ediff1d(lon_data))
dim_lat = np.unique(np.ediff1d(lat_data))
if (len(dim_lon) != 1) or (len(dim_lat) != 1):
print("The netCDF file is not a regular longitude/latitude grid")
return
The problem: when we use function np.unique(np.ediff1d(lon_data)), we get an array that has more than one element. Therefore there is an error about unregular grid. This is due to if state comparison applied to floating point numbers.
test_wu.zip

from geemap.

Sorry for the delay. This bug has been fixed in #1973

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