the position of the circle is offset when generating a two-level figure about circlify HOT 12 CLOSED

update:
l0=circ.circlify(a0,target_enclosure=circ.Circle(0,0,2048/1152-0.1),with_enclosure=True)
2048/1152 is my computer display resolution.i find adjust it can fix some circles.

from circlify.

Hey @rawenlei,

Thank you for taking the time to bring up this issue.

I am fixing the issue now. It should work in the next release and setting the target_enclosure with Circle(0, 0, 2048/1152) is just a happy coincidence that partially works around the problem.

from circlify.

I believe the issue is fixed by f68f69d. Could you give 0.9.2 a try when you get a chance and let me know if that's not the case?

from circlify.

Here is what I am getting now with this code:

def drawMutliCircle():
    a0=[0.8,0.2,0.1,0.05,0.05]
    a1=[0.3,0.2,0.2,0.1]
    a2=[0.1,0.05,0.05]
    a3=[0.05,0.04,0.01]
    l0=circ.circlify(a0,with_enclosure=True)
    l1=circ.circlify(a1,target_enclosure=circ.Circle(*l0[0]),with_enclosure=True)
    l2=circ.circlify(a2,target_enclosure=circ.Circle(*l0[1]),with_enclosure=True)
    l3=circ.circlify(a3,target_enclosure=circ.Circle(*l0[2]),with_enclosure=True)
    fig, ax = plt.subplots(figsize=(6,6))
    l=l0+l1+l2+l3
    colors = [plt.cm.Dark2(i / len(l)) for i in range(len(l))]
    for j in l:
        c=plt.Circle((j[0],j[1]),j[2],alpha=0.3,color=colors[l.index(j)-1])
        ax.add_patch(c)
    ax.plot()
    plt.show()

from circlify.

Hey @elmotec ,at first thank you very much!'
with the help of your circlify package, i can easily show the data visualization of circle packing by python.
please allow me to introduce the 'circlify' package which has the advantage of quick response and small footprint to others programmer.
the following is the display of circle packing with three-levels deep via your 'circlify' package.

from circlify.

Here is what I am getting now with this code:

def drawMutliCircle():
    a0=[0.8,0.2,0.1,0.05,0.05]
    a1=[0.3,0.2,0.2,0.1]
    a2=[0.1,0.05,0.05]
    a3=[0.05,0.04,0.01]
    l0=circ.circlify(a0,with_enclosure=True)
    l1=circ.circlify(a1,target_enclosure=circ.Circle(*l0[0]),with_enclosure=True)
    l2=circ.circlify(a2,target_enclosure=circ.Circle(*l0[1]),with_enclosure=True)
    l3=circ.circlify(a3,target_enclosure=circ.Circle(*l0[2]),with_enclosure=True)
    fig, ax = plt.subplots(figsize=(6,6))
    l=l0+l1+l2+l3
    colors = [plt.cm.Dark2(i / len(l)) for i in range(len(l))]
    for j in l:
        c=plt.Circle((j[0],j[1]),j[2],alpha=0.3,color=colors[l.index(j)-1])
        ax.add_patch(c)
    ax.plot()
    plt.show()

Hi, @elmotec, its a great package. Using it, I would like to make a similar plot. However, in the latest version 0.10.0,
I got this error

TypeError: circlify() got an unexpected keyword argument 'with_enclosure'

The input parameters of circ are

circ.circlify(data, target_enclosure=None, show_enclosure=False, datum_field='datum', id_field='id', children_field='children')

How could I make this plot in the latest version, or should I down-grade the package to earlier version. Please let me know.

from circlify.

Did you try to use show_enclosure=True instead of with_enclosure=True? I believe I changed the parameter name in version 0.10.

from circlify.

I tried to run the above pieces of code and got indeed this error:
NameError: name 'plt' is not defined

I figure out I should add this at the top:

import matplotlib.pyplot as plt
import circlify as circ

But now when running the code I get:

c=plt.Circle((j[0],j[1]),j[2],alpha=0.3,color=colors[l.index(j)-1])
TypeError: 'Circle' object is not subscriptable

Could anyone tell me what I am doing wrong?

Windows 7
Python 3.8
circlify 0.15.0
matplotlib 3.6.3 

Thanks !!

from circlify.

from circlify.

Thanks @rawenlei
I edited my question and updated the code to import matplotlib and circlify.
But a new error message appears a few lines below:

c=plt.Circle((j[0],j[1]),j[2],alpha=0.3,color=colors[l.index(j)-1])
TypeError: 'Circle' object is not subscriptable

from circlify.

Thanks @rawenlei for the hand. @abubelinha, could you try this?

import circlify as circ
import matplotlib.pyplot as plt

def drawMutliCircle():
    a0=[0.8,0.2,0.1,0.05,0.05]
    a1=[0.3,0.2,0.2,0.1]
    a2=[0.1,0.05,0.05]
    a3=[0.05,0.04,0.01]
    l0=circ.circlify(a0,with_enclosure=True)
    l1=circ.circlify(a1,target_enclosure=circ.Circle(*l0[0]),with_enclosure=True)
    l2=circ.circlify(a2,target_enclosure=circ.Circle(*l0[1]),with_enclosure=True)
    l3=circ.circlify(a3,target_enclosure=circ.Circle(*l0[2]),with_enclosure=True)
    fig, ax = plt.subplots(figsize=(6,6))
    l=l0+l1+l2+l3
    colors = [plt.cm.Dark2(i / len(l)) for i in range(len(l))]
    for j in l:
        # Circle is not subscriptable via j[0], j[1], j[2], one must use j.x, j.y, and j.r.
        c=plt.Circle((j.x,j.y),j.r, alpha=0.3,color=colors[l.index(j)-1])
        ax.add_patch(c)
    ax.plot()
    plt.show()


if __name__ == "__main__":
    drawMutliCircle()

If it still doesn't work, please check out how it's done in the tests. Also note that with_enclosure is now show_enclosure in later versions.

from circlify.

Locking this thread because it has moved quite far from the original issue. Please open a new issue if need be.

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