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mjsabby avatar mjsabby commented on September 7, 2024

Where is argsV defined here? If you give a compiling sample might be able to debug with you.

from llvmsharp.

anthony-y avatar anthony-y commented on September 7, 2024

This is basically taken from the Kladeiscope tutorials except using a tree walk instead of linearly.

_values is a Stack of LLVMValueRefs.

FunctionCallExpression is the type in my AST that represents a function call.

private void GenerateFunctionCall(FunctionCallExpression funcCallExpr)
{
    var func = LLVM.GetNamedFunction(_module, funcCallExpr.FunctionName);

    var argumentCount = (uint)funcCallExpr.Parameters.Count;
    var argsV = new LLVMValueRef[Math.Max(argumentCount, 1)];
    for (int i = 0; i < argumentCount; ++i)
    {
        Visit(funcCallExpr.Parameters[i]);
        argsV[i] = _values.Pop();
    }

    var returnType = LLVM.GetReturnType(LLVM.GetElementType(LLVM.TypeOf(func)));

    LLVM.BuildCall(_builder, func, out argsV[0], argumentCount, (returnType.Equals(LLVM.VoidType()) ? Marshal.PtrToStringAuto(IntPtr.Zero) : "fcall"));
}

Sorry for not providing enough info the first time around. Thanks for replying :)

from llvmsharp.

anthony-y avatar anthony-y commented on September 7, 2024

So I just changed this line:

LLVM.BuildCall(_builder, func, out argsV[0], argumentCount, (returnType.Equals(LLVM.VoidType()) ? Marshal.PtrToStringAuto(IntPtr.Zero) : "fcall"));

to

LLVM.BuildCall(_builder, func, out argsV[0], argumentCount, "");

and it works

facepalm

from llvmsharp.

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