Transform/runtime: Implement "named capturing groups" about regexp-tree HOT 5 CLOSED

yes, named groups count => x=1 y=3.

you can also use [null, 1, "year", 3, "month", "day"], then you simply loop through the array and store names[i]: originalMatch[i] in matches.groups, So, matches.groups["3"] would result in "y".

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that's 1/3 of what I currently do with regexp-tree.

Your example has only named groups. You can also have unnamed groups.
You need to collect an array of both group names and indexes of regular capturing groups (set name = index).

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@hg42, good point, yeah, the second parameter should be map from group name to the index. I think unnamed groups share the same index? I.e. this matches aaa:

/(?<foo>a)\1\k<foo>/

So perhaps:

/(x)(?<year>\d{4})-(y)(?<month>\d{2})-(?<day>\d{2})/

Would give:

new RegExpTree(/(x)(\d{4})-(y)(\d{2})-(\d{2})/, {year: 2, month: 4, day: 5});

from regexp-tree.

Transform part is done in f1233b9 and 7fb4b34.

from regexp-tree.

Local runtime support has been added in 0e6a9ff.

from regexp-tree.