Comments (7)
Hi Phi,
thanks! I love Geometor, beautiful work.
I'm in the middle of launching another project but I'd love to have a chat...
If you want to send me some contact details via my Contact page ( http://www.davidedc.com/contact/ ) we could try to arrange a call or something.
(P.S. The Root 3 B link doesn't seem to work at the moment)
from algebrite.
Thank you. I feel that I am just uncovering the beauty that is already there. These constructions are just the beginning of what I have been researching. There is so much more to demonstrate. I think it will amaze everyone. It is amazing me - that is why I am pretty much dedicating my life to this pursuit.
I will send a separate email with contact info. I think an initial conversation would be great.
All the best.
- Phi
PS - I forgot to push the Root-3-b yesterday. It is there now. http://i-am-phi.net/geometor-explorer/root3-b.html
from algebrite.
sorry - getting used to github.
from algebrite.
adding what line 12 is. Phi, you are saying that its expression is not "simplified enough" or rather is it simplified incorrectly?
What would you expect that expression to be?
from algebrite.
I apologize if my terminology is not correct - I am fairly new to this vocabulary :)
Line 12 is derived from points 39 & 44 (two highlighted points on circle 11 below) - which would make it parallel to Line 4. But the values are causing Line 12 and the related intersection points to occur in the wrong places. (But it does appear the y-intercept is in the correct place.)
Line 4 has m = -3^(1/2)
Line 12 has m = -3^(1/2) 5^(1/2) / (4 (1/4 + 1/4 5^(1/2))) - 3^(1/2) / (4 (1/4 + 1/4 5^(1/2)))
point 39:
x: -1/2 5^(1/2)
xVal: -1.11803
y: 0
yVal: 0
* parents: 2
0 : line
11 : circle
point 44:
x: 1/4 - 1/4 5^(1/2)
xVal: -0.309017
y: -1/4 3^(1/2) - 1/4 3^(1/2) 5^(1/2)
yVal: -1.40126
* parents: 2
6 : line
11 : circle
here is the rundown on Line 12
a: 1/4 3^(1/2) + 1/4 3^(1/2) 5^(1/2)
b: 1/4 + 1/4 5^(1/2)
c: 5/8 3^(1/2) + 1/8 3^(1/2) 5^(1/2)
eq: 1/4 y + 5/8 3^(1/2) + 1/4 3^(1/2) x + 1/8 3^(1/2) 5^(1/2) + 1/4 3^(1/2) 5^(1/2) x + 1/4 5^(1/2) y [ = 0 ]
m: -3^(1/2) 5^(1/2) / (4 (1/4 + 1/4 5^(1/2))) - 3^(1/2) / (4 (1/4 + 1/4 5^(1/2)))
n: -3^(1/2) 5^(1/2) / (8 (1/4 + 1/4 5^(1/2))) - 5 3^(1/2) / (8 (1/4 + 1/4 5^(1/2)))
eq2: [ y = ] (-3^(1/2) 5^(1/2) / (4 (1/4 + 1/4 5^(1/2))) - 3^(1/2) / (4 (1/4 + 1/4 5^(1/2)))) x - 3^(1/2) 5^(1/2) / (8 (1/4 + 1/4 5^(1/2))) - 5 3^(1/2) / (8 (1/4 + 1/4 5^(1/2)))
xRoot: (-5^(1/2) / ((3^(1/2) 5^(1/2) / (3^(1/2) + 3^(1/2) 5^(1/2)) + 3^(1/2) / (3^(1/2) + 3^(1/2) 5^(1/2))) (3^(1/2) + 3^(1/2) 5^(1/2))) - 1 / ((3^(1/2) 5^(1/2) / (3^(1/2) + 3^(1/2) 5^(1/2)) + 3^(1/2) / (3^(1/2) + 3^(1/2) 5^(1/2))) (3^(1/2) + 3^(1/2) 5^(1/2)))) y - 3^(1/2) 5^(1/2) / (2 (3^(1/2) 5^(1/2) / (3^(1/2) + 3^(1/2) 5^(1/2)) + 3^(1/2) / (3^(1/2) + 3^(1/2) 5^(1/2))) (3^(1/2) + 3^(1/2) 5^(1/2))) - 5 3^(1/2) / (2 (3^(1/2) 5^(1/2) / (3^(1/2) + 3^(1/2) 5^(1/2)) + 3^(1/2) / (3^(1/2) + 3^(1/2) 5^(1/2))) (3^(1/2) + 3^(1/2) 5^(1/2)))
yRoot: (-3^(1/2) 5^(1/2) / ((1 + 5^(1/2)) (1 / (1 + 5^(1/2)) + 5^(1/2) / (1 + 5^(1/2)))) - 3^(1/2) / ((1 + 5^(1/2)) (1 / (1 + 5^(1/2)) + 5^(1/2) / (1 + 5^(1/2))))) x - 3^(1/2) 5^(1/2) / (2 (1 + 5^(1/2)) (1 / (1 + 5^(1/2)) + 5^(1/2) / (1 + 5^(1/2)))) - 5 3^(1/2) / (2 (1 + 5^(1/2)) (1 / (1 + 5^(1/2)) + 5^(1/2) / (1 + 5^(1/2))))
points: 7
point : 39
point : 44
point : 47
point : 48
point : 49
point : 50
point : 51
in SVG-utils.js, I started creating some check/validation functions
you can run checkLine(elements[12])
in the console and see that I am getting different values for the xRoot
and yRoot
for eq
and eq
2 depending on whether I call simplify again.
This is very much a prototype. And I am kind of guessing on how to use Algebrite. But it all works up until the point values start getting a little complex. I have a near term goal to modularize the code and separate the algebra from the rest of the construction logic.
I will try to document what I am actually doing in deriving the equations and points.
from algebrite.
from a high-level perspective, Algebrite should really aim at giving you always "correct" line-line and line-circle intercept(s).
we'd need to see the actual steps used... from which of the two equations you isolate the first variable ("root" should always let you do that for degrees one and two so it should always work), how you substitute the obtained expression in the second equation, and then again how you "root" the second equation (to find either the x or the y of the intercepts).
Then I guess you substitute back to obtain the other variable (again Algebrite should be fixed to always work there), then to plot the values you want numerical values out of the symbolical ones, and "float" should be fixed to always give you those (and I've dealt with bugs in "float" before, so your points might be somewhere but it could be "float"'s fault that they are not where they should be).
So Algebrite should be fixed to always cover those steps.
It's another issue altogether whether the symbolic expressions that one gets for these points are in "good enough" shape that you can then still find phi from those expressions (or ratios of distances between these points, etc.)... this could be more complex to tackle especially if along the way there are "unwieldy" surds in the denominators and nested surds... we'd need to see what ends up in those expressions...
from algebrite.
Closing this to clean up my issues. (If only it were that easy)
Hope you are doing well.
from algebrite.
Related Issues (20)
- Solving Boolean expressions
- Solving systems of equations
- Absolute value syntax errors
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- Simplify
- GUI for user to edit/enter the equation in HTML
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- Update NPM version
- cann't simpifay apk
- the order of the powers of the polynomial is reversed HOT 1
- How to solve equations? HOT 2
- How to identify if an expression given by a human is in its simplified form HOT 4
- Is there some kind of AST ? HOT 1
- draw function is needed HOT 1
- Can't return numerical results < 1e-6. Can't substitute variables with scientific notation
- Infinite loop when try to inverse a 1x1 matrix
- Computation of binomial
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- simplification with exponents HOT 1
- i raised to exponents bigger than 4 is not calculated correctly
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from algebrite.