Comments (2)
itcharge
commented on June 16, 2024
1
您好 这里为什么成立？ logn这里的底数是10 如果用换底公式的话不应该是log_2 n / log_2 10 嘛
您好，这里原文中的公式写反了，改正后应该是
感谢指正，文中已修复。
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bbkxm
commented on June 16, 2024
您好 这里为什么成立？ logn这里的底数是10 如果用换底公式的话不应该是log_2 n / log_2 10 嘛
log₂ 10 ≈ 3.3223 ，1/log₂ 10 ≈ 0.301和k=3.322，差别也不大。loga n和logb n只有一个常数因子不同，这个因子在大O记法中被丢弃。因此记作O（log n），而不论对数的底是多少，是对数时间算法的标准记法
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