Comments (2)
I think this is similar to what @nbremer did in the “Creating a better chord ordering” section of Data-based orientations for gradients in a d3.js chord diagram.
(Except the position of the i -> i chords, which Nadieh didn't need.)
Nadieh's relevant code:
for(var m = 0; m < n; m++) {
numSeq[m] = (n+(i-1)-m)%n;
}
My fork:
const A = Array.from({ length: n }, (_, k) => (n + i - k) % n); // same as Nadieh’s I think
A.splice(Math.floor(n / 2), 0, A.shift()); // reinjects *i* in the center
from d3-chord.
We could keep the API mostly unchanged by passing the group's id i as a third argument to sortSubgroup?
from d3-chord.
Related Issues (12)
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from d3-chord.