Comments (1)
changkun
commented on May 21, 2024
这个过程需要仔细阅读代码，正文中的介绍可能不够详细，会在支持 C++17 的过程中修订这部分内容：
从普通传参 中可以看看出 reference(v); 始终是调用的左值引用，所以对于 void pass(T&& v) 内而言，v 是一个左值。std::move 的作用在于将一个左值转化为一个右值，这一点可以从 std::move 传参 的输出结果中得到验证。
from modern-cpp-tutorial.
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from modern-cpp-tutorial.