Add support for sending exceptions to Sentry about faktory_worker_python HOT 5 OPEN

    def _fail(self, jid: str, exception=None):
        super()._fail(jid, exception)
        if exception is not None:
            honeybadger.context(jid=jid)
            honeybadger.notify(exception)

import honeybadger
from faktory import Worker

# Configure Honeybadger
honeybadger.configure(api_key = 'your_api_key')

class HoneybadgerWorker(Worker):
    def _fail(self, jid: str, exception=None):
        response = {"jid": jid}
        if exception is not None:
            response["errtype"] = type(exception).__name__
            response["message"] = str(exception)
            # notify Honeybadger of the exception
            honeybadger.context(jid=jid)
            honeybadger.notify(exception)

        self.faktory.reply("FAIL", response)
        ok = next(self.faktory.get_message())

# Now, when you create a new worker class, inherit from HoneybadgerWorker instead of Worker

class MyWorker(HoneybadgerWorker):
    # Your worker code goes here
    pass