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HeQYT avatar HeQYT commented on June 30, 2024 4

I've solved the problem, change capital Y to lowercase y: '%m/%d/%Y' ----> '%m/%d/%y'!

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bnicholl avatar bnicholl commented on June 30, 2024 4

Use '%m/%d/%Y' when the year in the date looks like 6/15/2018. Use '%m/%d/%y' when the year in the date looks like 6/15/18

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Aisuko avatar Aisuko commented on June 30, 2024

@HeQYT Hi, Why to do this ? Did you research the reason? I have the same issue. But in another function only '%m/%d/%Y' can be worked.

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chenxuzhen avatar chenxuzhen commented on June 30, 2024

if you add a line of 'print(str(row[column_index]))' after 'a_date = datetime.date(datetime.strptime(
str(row[column_index]), '%m/%d/%y')), you'll find out that the str function converts date format '1/20/2014' to '1/20/14'.
That's why the lower case 'y' has to be used in this case.
print is a good debugging tool for simple scripting.
See my code:

#!/usr/bin/env python3
import csv
import MySQLdb
import sys
from datetime import datetime, date

#Path to and name of a CSV input file
input_file = sys.argv[1]

#Connect to a MySQL database
con = MySQLdb.connect(host='localhost', port=3306, db='my_suppliers', user='root', passwd='root@cxzsql')
c = con.cursor()

Read the CSV file

#Insert the data into the Suppliers table
file_reader = csv.reader(open(input_file, 'r', newline=''))
header = next(file_reader)
for row in file_reader:
data = []
for column_index in range(len(header)):
if column_index < 4:
data.append(str(row[column_index]).lstrip('$')
.replace(',', '').strip())
else:
a_date = datetime.date(datetime.strptime(
str(row[column_index]), '%m/%d/%y'))
print(str(row[column_index]))
# %Y: year is 2015; %y: year is 15
a_date = a_date.strftime('%Y-%m-%d')
#print(a_date)
data.append(a_date)
#print(data)
c.execute("""INSERT INTO Suppliers VALUES (%s, %s, %s, %s, %s);""", data)
con.commit()
print("")

Query the Suppliers table

c.execute("SELECT * FROM Suppliers")
rows = c.fetchall()
for row in rows:
row_list_output = []
for column_index in range(len(row)):
row_list_output.append(str(row[column_index]))
print(row_list_output)

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Gztabo21 avatar Gztabo21 commented on June 30, 2024

same the problem

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dnaveenit avatar dnaveenit commented on June 30, 2024

Same error, the following error is occurred in some random systems even-though datetime utilities not used in the code.

Traceback (most recent call last):
File "Test.py", line 192, in
File "winapps_init_.py", line 50, in search_installed
File "winapps_init_.py", line 42, in
File "winapps_init_.py", line 40, in
File "winapps_init_.py", line 186, in installed_application
File "winapps_init.py", line 106, in
File "_strptime.py", line 568, in _strptime_datetime
File "_strptime.py", line 349, in _strptime
ValueError: time data '12/11/2019' does not match format '%Y%m%d'

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its-proHAcker avatar its-proHAcker commented on June 30, 2024

you have to just remove "/" from the String and put "," in it .. Boom

Code Are Here
"import datetime as dt
str = '01,01,2017'
datetime_value = dt.datetime.strptime(str,'%d,%m,%Y')
print(datetime_value)"

#OutPut
2017-01-01 00:00:00

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