Comments (1)
commented on May 26, 2024
@param({"arg0","$._GET.arg0"})
public function doSomething1() {}
以上, $._GET.arg0没有在doSomething1方法中有对应参数,所以解析出错了, 路由没有加载成功, 看一下PHP的error_log, 应该有提示
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