Python mimeparse. about mimeparse HOT 2 CLOSED

Oops, sorry ...

Title should be: Python parse_mime_type does not handle header params correctly

What steps will reproduce the problem?

Run the following in a Python shell:

>>> mimeparse.parse_mime_type('type/subtype; param="=value="')

What is the expected output? What do you see instead?

Expected: ('type', 'subtype', {'param': '"=value="'})

Instead, it raises a ValueError.

What version of the product are you using? On what operating system?

v 0.1.2

Please provide any additional information below.

The problem is that it splits the param on *all* '=' chars instead of just the 
first. Changing line 32 to split using, param.split("=", 1), fixes the problem.

This issue was closed by revision r20.