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View Code? Open in Web Editor NEWstarter code for spring 21
starter code for spring 21
Hi CS61B Contributors,
I am from Brown and during this summer, I'm studying Java with this excellent course. Recently I'm doing project 2 Gitlet. The description of merge command says
If the split point is the current branch, then the effect is to check out the given branch.
However, it would be better if the difference between merge
with a fast-forward current branch and checkout
is further clarified. When merging in this condition,
For example, if we are at branch master
and HEAD
points to commit c1
. Branch other
points to commit c2
.
*master other
*------------*------------*------------*
c1 c2
After merge other
, the status is expected to be
*master
other
*------------*------------*------------*
c1 c2
However, if we only checkout other
, then the status is
master *other
*------------*------------*------------*
c1 c2
I'm not sure about the details about your autograder, but I believe it's better to add more clarification in the spec.
Thanks a lot.
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